import com.alibaba.fastjson.JSONObject; /** * Created by SYJ on 2017/9/13. */ public class MainTest { public static void main(String[] args) { String json = "{\"code\":0,\"message\":\"没有查询到数据\",\"data\":null,\&
#定义一个方法get_num(num),num参数是列表类型,判断列表里面的元素为数字类型.其他类型则报错,并且返回一个偶数列表:(注:列表里面的元素为偶数). def get_num(num): if type(num)!= list: return '您传入的不是列表!' else: for i in num: if not isinstance(i,int): return '请全部传入整数!' return list(filter(lambda x:x%2==0,num)) print(
小测试 in del.py import datetime cur = datetime.datetime.now() num = 1 a_list = {"a":1, "b":2, "c":3} while num < 100000: if "a" in a_list: pass num += 1 now = datetime.datetime.now() print (now - cur).total_seconds
原文:https://docs.quantifiedcode.com/python-anti-patterns/performance/using_key_in_list_to_check_if_key_is_contained_in_a_list.html 使用 key in list 去迭代list会潜在的花费n次迭代才能完成,n为该key在list中位置.允许的话,可以将list转成set或者dict, 因为Python在set或dict中查找元素是通过直接访问他们而不需要迭代,这会高效很
d = {: , : , : , : , : , : } def is_key_present(x): if x in d: print('Key is present in the dictionary') else: print('Key is not present in the dictionary') is_key_present() is_key_present()
using Newtonsoft.Json; using StackExchange.Redis; using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading.Tasks; namespace AIMS.RedisMng { public class RedisContext : IRedisContext { private readon